(2x-6)/(x+2)=3

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Solution for (2x-6)/(x+2)=3 equation: 



(2x-6)/(x+2)=3

We move all terms to the left:

(2x-6)/(x+2)-(3)=0



Domain of the equation: (x+2)!=0

We move all terms containing x to the left, all other terms to the right

x!=-2

x∈R



We multiply all the terms by the denominator


(2x-6)-3*(x+2)=0

We multiply parentheses

(2x-6)-3x-6=0

We get rid of parentheses

2x-3x-6-6=0

We add all the numbers together, and all the variables

-1x-12=0

We move all terms containing x to the left, all other terms to the right

-x=12

x=12/-1

x=-12

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