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(2x-6)/(x+2)=7
We move all terms to the left:
(2x-6)/(x+2)-(7)=0
Domain of the equation: (x+2)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
x!=-2
x∈R
(2x-6)-7*(x+2)=0
We multiply parentheses
(2x-6)-7x-14=0
We get rid of parentheses
2x-7x-6-14=0
We add all the numbers together, and all the variables
-5x-20=0
We move all terms containing x to the left, all other terms to the right
-5x=20
x=20/-5
x=-4
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