(2x-6)/3=5+(x+2)/4

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Solution for (2x-6)/3=5+(x+2)/4 equation:



(2x-6)/3=5+(x+2)/4
We move all terms to the left:
(2x-6)/3-(5+(x+2)/4)=0
We calculate fractions
2x/()+(-(5+(x+2)*3)/()=0
We calculate terms in parentheses: +(-(5+(x+2)*3)/(), so:
-(5+(x+2)*3)/(
We multiply all the terms by the denominator
-(5+(x+2)*3)
We calculate terms in parentheses: -(5+(x+2)*3), so:
5+(x+2)*3
determiningTheFunctionDomain (x+2)*3+5
We multiply parentheses
3x+6+5
We add all the numbers together, and all the variables
3x+11
Back to the equation:
-(3x+11)
We get rid of parentheses
-3x-11
Back to the equation:
+(-3x-11)
We get rid of parentheses
2x/()-3x-11=0
We multiply all the terms by the denominator
2x-3x*()-11*()=0
We add all the numbers together, and all the variables
2x-3x*()=0

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