(2x-67)+(x-17)+(3x)=260

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Solution for (2x-67)+(x-17)+(3x)=260 equation: 



(2x-67)+(x-17)+(3x)=260

We move all terms to the left:

(2x-67)+(x-17)+(3x)-(260)=0

We add all the numbers together, and all the variables

3x+(2x-67)+(x-17)-260=0

We get rid of parentheses

3x+2x+x-67-17-260=0

We add all the numbers together, and all the variables

6x-344=0

We move all terms containing x to the left, all other terms to the right

6x=344

x=344/6

x=57+1/3

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