(2x-67)+(x-17)+(3x)=260

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Solution for (2x-67)+(x-17)+(3x)=260 equation:



(2x-67)+(x-17)+(3x)=260
We move all terms to the left:
(2x-67)+(x-17)+(3x)-(260)=0
We add all the numbers together, and all the variables
3x+(2x-67)+(x-17)-260=0
We get rid of parentheses
3x+2x+x-67-17-260=0
We add all the numbers together, and all the variables
6x-344=0
We move all terms containing x to the left, all other terms to the right
6x=344
x=344/6
x=57+1/3

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