(2x-7)(2x+9)=0

Solution for (2x-7)(2x+9)=0 equation:

(2x-7)(2x+9)=0

We multiply parentheses ..

(+4x^2+18x-14x-63)=0

We get rid of parentheses

4x^2+18x-14x-63=0

We add all the numbers together, and all the variables

4x^2+4x-63=0

a = 4; b = 4; c = -63;
Δ = b2-4ac
Δ = 42-4·4·(-63)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-32}{2*4}=\frac{-36}{8}
=-4+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+32}{2*4}=\frac{28}{8}
=3+1/2
$