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(2x-7)(2x-7)-4=0
We multiply parentheses ..
(+4x^2-14x-14x+49)-4=0
We get rid of parentheses
4x^2-14x-14x+49-4=0
We add all the numbers together, and all the variables
4x^2-28x+45=0
a = 4; b = -28; c = +45;
Δ = b2-4ac
Δ = -282-4·4·45
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{64}=8$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-8}{2*4}=\frac{20}{8} =2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+8}{2*4}=\frac{36}{8} =4+1/2 $
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