(2x-7)(3x+1)=(2x-5)(3x+1)

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Solution for (2x-7)(3x+1)=(2x-5)(3x+1) equation:



(2x-7)(3x+1)=(2x-5)(3x+1)
We move all terms to the left:
(2x-7)(3x+1)-((2x-5)(3x+1))=0
We multiply parentheses ..
(+6x^2+2x-21x-7)-((2x-5)(3x+1))=0
We calculate terms in parentheses: -((2x-5)(3x+1)), so:
(2x-5)(3x+1)
We multiply parentheses ..
(+6x^2+2x-15x-5)
We get rid of parentheses
6x^2+2x-15x-5
We add all the numbers together, and all the variables
6x^2-13x-5
Back to the equation:
-(6x^2-13x-5)
We get rid of parentheses
6x^2-6x^2+2x-21x+13x-7+5=0
We add all the numbers together, and all the variables
-6x-2=0
We move all terms containing x to the left, all other terms to the right
-6x=2
x=2/-6
x=-1/3

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