(2x-7)(3x+1)=388

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Solution for (2x-7)(3x+1)=388 equation:



(2x-7)(3x+1)=388
We move all terms to the left:
(2x-7)(3x+1)-(388)=0
We multiply parentheses ..
(+6x^2+2x-21x-7)-388=0
We get rid of parentheses
6x^2+2x-21x-7-388=0
We add all the numbers together, and all the variables
6x^2-19x-395=0
a = 6; b = -19; c = -395;
Δ = b2-4ac
Δ = -192-4·6·(-395)
Δ = 9841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{9841}}{2*6}=\frac{19-\sqrt{9841}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{9841}}{2*6}=\frac{19+\sqrt{9841}}{12} $

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