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(2x-7)(3x-9)-(5x-9)(x-4)=(x-3)(x-4)
We move all terms to the left:
(2x-7)(3x-9)-(5x-9)(x-4)-((x-3)(x-4))=0
We multiply parentheses ..
(+6x^2-18x-21x+63)-(5x-9)(x-4)-((x-3)(x-4))=0
We calculate terms in parentheses: -((x-3)(x-4)), so:We get rid of parentheses
(x-3)(x-4)
We multiply parentheses ..
(+x^2-4x-3x+12)
We get rid of parentheses
x^2-4x-3x+12
We add all the numbers together, and all the variables
x^2-7x+12
Back to the equation:
-(x^2-7x+12)
6x^2-x^2-18x-21x-(5x-9)(x-4)+7x+63-12=0
We multiply parentheses ..
6x^2-x^2-(+5x^2-20x-9x+36)-18x-21x+7x+63-12=0
We add all the numbers together, and all the variables
5x^2-(+5x^2-20x-9x+36)-32x+51=0
We get rid of parentheses
5x^2-5x^2+20x+9x-32x-36+51=0
We add all the numbers together, and all the variables
-3x+15=0
We move all terms containing x to the left, all other terms to the right
-3x=-15
x=-15/-3
x=+5
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