(2x-7)+(3x-2)=x+19

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Solution for (2x-7)+(3x-2)=x+19 equation: 



(2x-7)+(3x-2)=x+19

We move all terms to the left:

(2x-7)+(3x-2)-(x+19)=0

We get rid of parentheses

2x+3x-x-7-2-19=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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