(2x-7)+(7x+5)+(8+x)=N

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Solution for (2x-7)+(7x+5)+(8+x)=N equation: 



(2x-7)+(7x+5)+(8+x)=

We move all terms to the left:

(2x-7)+(7x+5)+(8+x)-()=0

We add all the numbers together, and all the variables

(2x-7)+(7x+5)+(x+8)-()=0

We add all the numbers together, and all the variables

(2x-7)+(7x+5)+(x+8)=0

We get rid of parentheses

2x+7x+x-7+5+8=0

We add all the numbers together, and all the variables

10x+6=0

We move all terms containing x to the left, all other terms to the right

10x=-6

x=-6/10

x=-3/5

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