(2x-7)/(4)+x=(2x+7)/(2)+8

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Solution for (2x-7)/(4)+x=(2x+7)/(2)+8 equation: 



(2x-7)/(4)+x=(2x+7)/(2)+8

We move all terms to the left:

(2x-7)/(4)+x-((2x+7)/(2)+8)=0

We add all the numbers together, and all the variables

x+(2x-7)/4-((2x+7)/2+8)=0

We calculate fractions


x+(4x-14)/()+(-((2x+7)*4)/()=0



We calculate terms in parentheses: +(-((2x+7)*4)/(), so:

-((2x+7)*4)/(

We multiply all the terms by the denominator


-((2x+7)*4)



We calculate terms in parentheses: -((2x+7)*4), so:

(2x+7)*4

We multiply parentheses

8x+28

Back to the equation:

-(8x+28)



We get rid of parentheses

-8x-28

Back to the equation:

+(-8x-28)



We get rid of parentheses

x+(4x-14)/()-8x-28=0

We multiply all the terms by the denominator


x*()+(4x-14)-8x*()-28*()=0

We add all the numbers together, and all the variables

x*()+(4x-14)-8x*()=0

We get rid of parentheses

x*()+4x-8x*()-14=0

We add all the numbers together, and all the variables

4x+x*()-8x*()-14=0

We move all terms containing x to the left, all other terms to the right

4x+x*()-8x*()=14

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