(2x-7)/(x+1)=(2x)/(x+4)

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Solution for (2x-7)/(x+1)=(2x)/(x+4) equation:


D( x )

x+4 = 0

x+1 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-4) U (-4:-1) U (-1:+oo)

(2*x-7)/(x+1) = (2*x)/(x+4) // - (2*x)/(x+4)

(2*x-7)/(x+1)-((2*x)/(x+4)) = 0

(2*x-7)/(x+1)-2*x*(x+4)^-1 = 0

(2*x-7)/(x+1)+(-2*x)/(x+4) = 0

((2*x-7)*(x+4))/((x+1)*(x+4))+(-2*x*(x+1))/((x+1)*(x+4)) = 0

(2*x-7)*(x+4)-2*x*(x+1) = 0

-x-28 = 0

(-x-28)/((x+1)*(x+4)) = 0

(-x-28)/((x+1)*(x+4)) = 0 // * (x+1)*(x+4)

-x-28 = 0

-x-28 = 0 // + 28

-x = 28 // * -1

x = -28

x = -28

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