(2x-7)/7=(9x-2)/3

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Solution for (2x-7)/7=(9x-2)/3 equation: 



(2x-7)/7=(9x-2)/3

We move all terms to the left:

(2x-7)/7-((9x-2)/3)=0

We calculate fractions


2x/()+(-((9x-2)*7)/()=0



We calculate terms in parentheses: +(-((9x-2)*7)/(), so:

-((9x-2)*7)/(

We multiply all the terms by the denominator


-((9x-2)*7)



We calculate terms in parentheses: -((9x-2)*7), so:

(9x-2)*7

We multiply parentheses

63x-14

Back to the equation:

-(63x-14)



We get rid of parentheses

-63x+14

Back to the equation:

+(-63x+14)



We get rid of parentheses

2x/()-63x+14=0

We multiply all the terms by the denominator


2x-63x*()+14*()=0

We add all the numbers together, and all the variables

2x-63x*()=0

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