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(2x-7-4)=(x+3-3)
We move all terms to the left:
(2x-7-4)-((x+3-3))=0
We add all the numbers together, and all the variables
(2x-11)-((+x))=0
We get rid of parentheses
2x-((+x))-11=0
We calculate terms in parentheses: -((+x)), so:We add all the numbers together, and all the variables
(+x)
We get rid of parentheses
x
Back to the equation:
-(x)
x-11=0
We move all terms containing x to the left, all other terms to the right
x=11
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