(2x-8)(2x+10)=4x*x-64

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Solution for (2x-8)(2x+10)=4x*x-64 equation:



(2x-8)(2x+10)=4x*x-64
We move all terms to the left:
(2x-8)(2x+10)-(4x*x-64)=0
We get rid of parentheses
(2x-8)(2x+10)-4x*x+64=0
We multiply parentheses ..
(+4x^2+20x-16x-80)-4x*x+64=0
Wy multiply elements
(+4x^2+20x-16x-80)-4x^2+64=0
We get rid of parentheses
4x^2-4x^2+20x-16x-80+64=0
We add all the numbers together, and all the variables
4x-16=0
We move all terms containing x to the left, all other terms to the right
4x=16
x=16/4
x=4

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