(2x-8)(3x+12)=0

Solution for (2x-8)(3x+12)=0 equation:

Simplifying
(2x + -8)(3x + 12) = 0

Reorder the terms:
(-8 + 2x)(3x + 12) = 0

Reorder the terms:
(-8 + 2x)(12 + 3x) = 0

Multiply (-8 + 2x) * (12 + 3x)
(-8(12 + 3x) + 2x * (12 + 3x)) = 0
((12 * -8 + 3x * -8) + 2x * (12 + 3x)) = 0
((-96 + -24x) + 2x * (12 + 3x)) = 0
(-96 + -24x + (12 * 2x + 3x * 2x)) = 0
(-96 + -24x + (24x + 6x2)) = 0

Combine like terms: -24x + 24x = 0
(-96 + 0 + 6x2) = 0
(-96 + 6x2) = 0

Solving
-96 + 6x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '96' to each side of the equation.
-96 + 96 + 6x2 = 0 + 96

Combine like terms: -96 + 96 = 0
0 + 6x2 = 0 + 96
6x2 = 0 + 96

Combine like terms: 0 + 96 = 96
6x2 = 96

Divide each side by '6'.
x2 = 16

Simplifying
x2 = 16

Take the square root of each side:
x = {-4, 4}