(2x-8)(3x-1)=0

Solution for (2x-8)(3x-1)=0 equation:

(2x-8)(3x-1)=0

We multiply parentheses ..

(+6x^2-2x-24x+8)=0

We get rid of parentheses

6x^2-2x-24x+8=0

We add all the numbers together, and all the variables

6x^2-26x+8=0

a = 6; b = -26; c = +8;
Δ = b2-4ac
Δ = -262-4·6·8
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-22}{2*6}=\frac{4}{12}
=1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+22}{2*6}=\frac{48}{12}
=4
$