(2x-8)(x+10)=352

Solution for (2x-8)(x+10)=352 equation:

(2x-8)(x+10)=352

We move all terms to the left:

(2x-8)(x+10)-(352)=0

We multiply parentheses ..

(+2x^2+20x-8x-80)-352=0

We get rid of parentheses

2x^2+20x-8x-80-352=0

We add all the numbers together, and all the variables

2x^2+12x-432=0

a = 2; b = 12; c = -432;
Δ = b2-4ac
Δ = 122-4·2·(-432)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-60}{2*2}=\frac{-72}{4}
=-18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+60}{2*2}=\frac{48}{4}
=12
$