(2x-8)+(x+23)=(4x-20)

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Solution for (2x-8)+(x+23)=(4x-20) equation: 



(2x-8)+(x+23)=(4x-20)

We move all terms to the left:

(2x-8)+(x+23)-((4x-20))=0

We get rid of parentheses

2x+x-((4x-20))-8+23=0



We calculate terms in parentheses: -((4x-20)), so:

(4x-20)

We get rid of parentheses

4x-20

Back to the equation:

-(4x-20)



We add all the numbers together, and all the variables

3x-(4x-20)+15=0

We get rid of parentheses

3x-4x+20+15=0

We add all the numbers together, and all the variables

-1x+35=0

We move all terms containing x to the left, all other terms to the right

-x=-35

x=-35/-1

x=+35

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