(2x-8)+(x-4)=21

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Solution for (2x-8)+(x-4)=21 equation: 



(2x-8)+(x-4)=21

We move all terms to the left:

(2x-8)+(x-4)-(21)=0

We get rid of parentheses

2x+x-8-4-21=0

We add all the numbers together, and all the variables

3x-33=0

We move all terms containing x to the left, all other terms to the right

3x=33

x=33/3

x=11

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