(2x-8)+64+(x-20)=180

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Solution for (2x-8)+64+(x-20)=180 equation: 



(2x-8)+64+(x-20)=180

We move all terms to the left:

(2x-8)+64+(x-20)-(180)=0

We add all the numbers together, and all the variables

(2x-8)+(x-20)-116=0

We get rid of parentheses

2x+x-8-20-116=0

We add all the numbers together, and all the variables

3x-144=0

We move all terms containing x to the left, all other terms to the right

3x=144

x=144/3

x=48

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