(2x-8)9x+4)=0

Solution for (2x-8)9x+4)=0 equation:

(2x-8)9x+4)=0

We add all the numbers together, and all the variables

(2x-8)9x=0

We multiply parentheses

18x^2-72x=0

a = 18; b = -72; c = 0;
Δ = b2-4ac
Δ = -722-4·18·0
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-72}{2*18}=\frac{0}{36}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+72}{2*18}=\frac{144}{36}
=4
$