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(2x-9)(7x+2)=0
We multiply parentheses ..
(+14x^2+4x-63x-18)=0
We get rid of parentheses
14x^2+4x-63x-18=0
We add all the numbers together, and all the variables
14x^2-59x-18=0
a = 14; b = -59; c = -18;
Δ = b2-4ac
Δ = -592-4·14·(-18)
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4489}=67$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-67}{2*14}=\frac{-8}{28} =-2/7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+67}{2*14}=\frac{126}{28} =4+1/2 $
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