(2x-9)*3x=2

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Solution for (2x-9)*3x=2 equation:



(2x-9)*3x=2
We move all terms to the left:
(2x-9)*3x-(2)=0
We multiply parentheses
6x^2-27x-2=0
a = 6; b = -27; c = -2;
Δ = b2-4ac
Δ = -272-4·6·(-2)
Δ = 777
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{777}}{2*6}=\frac{27-\sqrt{777}}{12} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{777}}{2*6}=\frac{27+\sqrt{777}}{12} $

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