(2x-9)+(11x-31)=(6x+26)

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Solution for (2x-9)+(11x-31)=(6x+26) equation: 



(2x-9)+(11x-31)=(6x+26)

We move all terms to the left:

(2x-9)+(11x-31)-((6x+26))=0

We get rid of parentheses

2x+11x-((6x+26))-9-31=0



We calculate terms in parentheses: -((6x+26)), so:

(6x+26)

We get rid of parentheses

6x+26

Back to the equation:

-(6x+26)



We add all the numbers together, and all the variables

13x-(6x+26)-40=0

We get rid of parentheses

13x-6x-26-40=0

We add all the numbers together, and all the variables

7x-66=0

We move all terms containing x to the left, all other terms to the right

7x=66

x=66/7

x=9+3/7

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