(2x-9)+(6x+26)=(11x-31)

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Solution for (2x-9)+(6x+26)=(11x-31) equation: 



(2x-9)+(6x+26)=(11x-31)

We move all terms to the left:

(2x-9)+(6x+26)-((11x-31))=0

We get rid of parentheses

2x+6x-((11x-31))-9+26=0



We calculate terms in parentheses: -((11x-31)), so:

(11x-31)

We get rid of parentheses

11x-31

Back to the equation:

-(11x-31)



We add all the numbers together, and all the variables

8x-(11x-31)+17=0

We get rid of parentheses

8x-11x+31+17=0

We add all the numbers together, and all the variables

-3x+48=0

We move all terms containing x to the left, all other terms to the right

-3x=-48

x=-48/-3

x=+16

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