(2x-9)-(3x-3)=-(-3+x)-2x+9

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Solution for (2x-9)-(3x-3)=-(-3+x)-2x+9 equation:



(2x-9)-(3x-3)=-(-3+x)-2x+9
We move all terms to the left:
(2x-9)-(3x-3)-(-(-3+x)-2x+9)=0
We add all the numbers together, and all the variables
(2x-9)-(3x-3)-(-(x-3)-2x+9)=0
We get rid of parentheses
2x-3x-(-(x-3)-2x+9)-9+3=0
We calculate terms in parentheses: -(-(x-3)-2x+9), so:
-(x-3)-2x+9
We add all the numbers together, and all the variables
-2x-(x-3)+9
We get rid of parentheses
-2x-x+3+9
We add all the numbers together, and all the variables
-3x+12
Back to the equation:
-(-3x+12)
We add all the numbers together, and all the variables
-1x-(-3x+12)-6=0
We get rid of parentheses
-1x+3x-12-6=0
We add all the numbers together, and all the variables
2x-18=0
We move all terms containing x to the left, all other terms to the right
2x=18
x=18/2
x=9

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