(2x-9)-(3x-3)=-(-3+x)-2x+9

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Solution for (2x-9)-(3x-3)=-(-3+x)-2x+9 equation: 



(2x-9)-(3x-3)=-(-3+x)-2x+9

We move all terms to the left:

(2x-9)-(3x-3)-(-(-3+x)-2x+9)=0

We add all the numbers together, and all the variables

(2x-9)-(3x-3)-(-(x-3)-2x+9)=0

We get rid of parentheses

2x-3x-(-(x-3)-2x+9)-9+3=0



We calculate terms in parentheses: -(-(x-3)-2x+9), so:

-(x-3)-2x+9

We add all the numbers together, and all the variables

-2x-(x-3)+9

We get rid of parentheses

-2x-x+3+9

We add all the numbers together, and all the variables

-3x+12

Back to the equation:

-(-3x+12)



We add all the numbers together, and all the variables

-1x-(-3x+12)-6=0

We get rid of parentheses

-1x+3x-12-6=0

We add all the numbers together, and all the variables

2x-18=0

We move all terms containing x to the left, all other terms to the right

2x=18

x=18/2

x=9

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