(2x-9/x-7)+x/2=-4/x-7

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Solution for (2x-9/x-7)+x/2=-4/x-7 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x+x/2-(9/x)-7 = -4/x-7 // + -4/x-7

2*x+x/2-(9/x)-(-4/x)-7+7 = 0

2*x+x/2-9*x^-1+4*x^-1-7+7 = 0

5/2*x^1-5*x^-1 = 0

(5/2*x^2-5*x^0)/(x^1) = 0 // * x^2

x^1*(5/2*x^2-5*x^0) = 0

x^1

(5/2)*x^2-5 = 0

(5/2)*x^2-5 = 0

DELTA = 0^2-(-5*4*(5/2))

DELTA = 50

DELTA > 0

x = (50^(1/2)+0)/(2*(5/2)) or x = (0-50^(1/2))/(2*(5/2))

x = 2^(1/2) or x = -2^(1/2)

x in { -2^(1/2), 2^(1/2)} 

x in { -2^(1/2), 2^(1/2) }

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