(2x/(x-3))+(1/x)=4

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Solution for (2x/(x-3))+(1/x)=4 equation: 



(2x/(x-3))+(1/x)=4

We move all terms to the left:

(2x/(x-3))+(1/x)-(4)=0



Domain of the equation: (x-3))!=0

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(2x/(x-3))+(+1/x)-4=0

We get rid of parentheses

(2x/(x-3))+1/x-4=0

We calculate fractions


((2x*x)/(-2x^2)+(1*(x-3)))/(-2x^2)-4=0



We calculate terms in parentheses: +((2x*x)/(-2x^2)+(1*(x-3)))/(-2x^2), so:

(2x*x)/(-2x^2)+(1*(x-3)))/(-2x^2

determiningTheFunctionDomain
(2x*x)/(-2x^2)-2x^2+(1*(x-3)))/(

We add all the numbers together, and all the variables

(+2x*x)/(-2x^2)-2x^2+(1*(x-3)))/(

We add all the numbers together, and all the variables

-2x^2+(+2x*x)/(-2x^2)+(1*(x-3)))/(

We calculate fractions


-2x^2+((+2x*x)*()/((-2x^2)*()+(-2x^2)+(1*(x-3)))*()/((-2x^2)*()



We calculate terms in parentheses: +((+2x*x)*()/((-2x^2)*()+(-2x^2)+(1*(x-3)))*()/((-2x^2)*(), so:

(+2x*x)*()/((-2x^2)*()+(-2x^2)+(1*(x-3)))*()/((-2x^2)*(

We can not solve this equation

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