(2x/12)+(3/12)=(7/12)x-1

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Solution for (2x/12)+(3/12)=(7/12)x-1 equation: 



(2x/12)+(3/12)=(7/12)x-1

We move all terms to the left:

(2x/12)+(3/12)-((7/12)x-1)=0



Domain of the equation: 12)x-1)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2x/12)-((+7/12)x-1)+(+3/12)=0

We get rid of parentheses

2x/12-((+7/12)x-1)+3/12=0

We calculate fractions


=0

x=0/1

x=0

Równanie nie ma rozwiązania

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