(2x/2x+4)+(15/5x+10)=(24/6x+12)

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Solution for (2x/2x+4)+(15/5x+10)=(24/6x+12) equation: 



(2x/2x+4)+(15/5x+10)=(24/6x+12)

We move all terms to the left:

(2x/2x+4)+(15/5x+10)-((24/6x+12))=0



Domain of the equation: 2x+4)!=0

x∈R





Domain of the equation: 5x+10)!=0

x∈R





Domain of the equation: 6x+12))!=0

x∈R



We get rid of parentheses

2x/2x+15/5x-((24/6x+12))+4+10=0

Fractions to decimals

15/5x-((24/6x+12))+4+10+1=0

We calculate fractions


90x/30x^2+(-((24*5x)/30x^2+4+10+1=0

We add all the numbers together, and all the variables

90x/30x^2+(-((+24*5x)/30x^2+4+10+1=0

We calculate fractions

We do not support expression: x^4

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