(2x/3)+((9x+2)/6)=x/2

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Solution for (2x/3)+((9x+2)/6)=x/2 equation: 



(2x/3)+((9x+2)/6)=x/2

We move all terms to the left:

(2x/3)+((9x+2)/6)-(x/2)=0

We add all the numbers together, and all the variables

(+2x/3)+((9x+2)/6)-(+x/2)=0

We get rid of parentheses

2x/3+((9x+2)/6)-x/2=0

We calculate fractions


(((9x+2)*3*2)/()+(-108x^2)/()+24x^2/()=0



We calculate terms in parentheses: +(((9x+2)*3*2)/()+(-108x^2)/()+24x^2/(), so:

((9x+2)*3*2)/()+(-108x^2)/()+24x^2/(

determiningTheFunctionDomain
(-108x^2)/()+24x^2/(+((9x+2)*3*2)/()

We can not solve this equation

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