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(2x/3)+(4/5)=(3x/4)-4
We move all terms to the left:
(2x/3)+(4/5)-((3x/4)-4)=0
We add all the numbers together, and all the variables
(+2x/3)-((+3x/4)-4)+(+4/5)=0
We get rid of parentheses
2x/3-((+3x/4)-4)+4/5=0
We calculate fractions
40x^2/()+(-((+3x*3*5)/()+()/()=0
We calculate terms in parentheses: +(-((+3x*3*5)/()+()/(), so:
-((+3x*3*5)/()+()/(
We can not solve this equation
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