(2x/3)+(x-4/2)=5

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Solution for (2x/3)+(x-4/2)=5 equation: 



(2x/3)+(x-4/2)=5

We move all terms to the left:

(2x/3)+(x-4/2)-(5)=0

We add all the numbers together, and all the variables

(+2x/3)+(x-2)-5=0

We get rid of parentheses

2x/3+x-2-5=0

We multiply all the terms by the denominator


2x+x*3-2*3-5*3=0

We add all the numbers together, and all the variables

2x+x*3-21=0

Wy multiply elements

2x+3x-21=0

We add all the numbers together, and all the variables

5x-21=0

We move all terms containing x to the left, all other terms to the right

5x=21

x=21/5

x=4+1/5

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