(2x/3)+(x/2)=(1/6)

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Solution for (2x/3)+(x/2)=(1/6) equation: 



(2x/3)+(x/2)=(1/6)

We move all terms to the left:

(2x/3)+(x/2)-((1/6))=0

We add all the numbers together, and all the variables

(+2x/3)+(+x/2)-((+1/6))=0

We get rid of parentheses

2x/3+x/2-((+1/6))=0

We calculate fractions


144x^2/()+108x^2/()+()/()=0

We add all the numbers together, and all the variables

144x^2/()+108x^2/()+1=0

We multiply all the terms by the denominator


144x^2+108x^2+1*()=0

We add all the numbers together, and all the variables

252x^2=0

a = 252; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·252·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{504}=0$

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