(2x/3)-(3x+3/5)=2

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Solution for (2x/3)-(3x+3/5)=2 equation: 


x in (-oo:+oo)

(2*x)/3-(3*x)-(3/5) = 2 // - 2

(2*x)/3-(3*x)-(3/5)-2 = 0

(2*x)/3-3*x-3/5-2 = 0

-7/3*x-13/5 = 0 // + 13/5

-7/3*x = 13/5 // : -7/3

x = 13/5/(-7/3)

x = -39/35

x = -39/35

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