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(2x/3)-(x/2)=(5/12)
We move all terms to the left:
(2x/3)-(x/2)-((5/12))=0
We add all the numbers together, and all the variables
(+2x/3)-(+x/2)-((+5/12))=0
We get rid of parentheses
2x/3-x/2-((+5/12))=0
We calculate fractions
(-36x^2)/()+48x^2/()+()/()=0
We add all the numbers together, and all the variables
(-36x^2)/()+48x^2/()+1=0
We multiply all the terms by the denominator
(-36x^2)+48x^2+1*()=0
We add all the numbers together, and all the variables
48x^2+(-36x^2)=0
We get rid of parentheses
48x^2-36x^2=0
We add all the numbers together, and all the variables
12x^2=0
a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{24}=0$
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