(2x/3)-4=(3x/2)+3x

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Solution for (2x/3)-4=(3x/2)+3x equation: 



(2x/3)-4=(3x/2)+3x

We move all terms to the left:

(2x/3)-4-((3x/2)+3x)=0



Domain of the equation: 2)+3x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2x/3)-((+3x/2)+3x)-4=0

We get rid of parentheses

2x/3-((+3x/2)+3x)-4=0

We calculate fractions


4x^2/6x+(-((+3x*3)/6x-4=0

We calculate fractions

We do not support expression: x^3

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