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(2x/3)=(32/6)
We move all terms to the left:
(2x/3)-((32/6))=0
We add all the numbers together, and all the variables
(+2x/3)-((+32/6))=0
We get rid of parentheses
2x/3-((+32/6))=0
We calculate fractions
12x^2/()+()/()=0
We add all the numbers together, and all the variables
12x^2/()+1=0
We multiply all the terms by the denominator
12x^2+1*()=0
We add all the numbers together, and all the variables
12x^2=0
a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{24}=0$
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