(2x/5)=(3x-27)

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Solution for (2x/5)=(3x-27) equation: 



(2x/5)=(3x-27)

We move all terms to the left:

(2x/5)-((3x-27))=0

We add all the numbers together, and all the variables

(+2x/5)-((3x-27))=0

We get rid of parentheses

2x/5-((3x-27))=0

We multiply all the terms by the denominator


2x-(((3x-27)))*5=0

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