(2x/5)=(8x/x-4)

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Solution for (2x/5)=(8x/x-4) equation: 



(2x/5)=(8x/x-4)

We move all terms to the left:

(2x/5)-((8x/x-4))=0



Domain of the equation: x-4))!=0

x∈R



We add all the numbers together, and all the variables

(+2x/5)-((8x/x-4))=0

We get rid of parentheses

2x/5-((8x/x-4))=0

We calculate fractions


2x^2/5x+(-((8x*5)/5x=0

We add all the numbers together, and all the variables

2x^2/5x+(-((+8x*5)/5x=0

We multiply all the terms by the denominator


2x^2+(-((+8x*5)=0



We calculate terms in parentheses: +(-((+8x*5), so:

-((+8x*5





We calculate terms in parentheses: +(-((+8x*5), so:

-((+8x*5





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-((+8x*5





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-((+8x*5





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-((+8x*5





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-((+8x*5





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-((+8x*5





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-((+8x*5





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-((+8x*5





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-((+8x*5





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-((+8x*5





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-((+8x*5





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-((+8x*5





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-((+8x*5





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-((+8x*5





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-((+8x*5





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