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(2x/5)=x-3
We move all terms to the left:
(2x/5)-(x-3)=0
We add all the numbers together, and all the variables
(+2x/5)-(x-3)=0
We get rid of parentheses
2x/5-x+3=0
We multiply all the terms by the denominator
2x-x*5+3*5=0
We add all the numbers together, and all the variables
2x-x*5+15=0
Wy multiply elements
2x-5x+15=0
We add all the numbers together, and all the variables
-3x+15=0
We move all terms containing x to the left, all other terms to the right
-3x=-15
x=-15/-3
x=+5
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