(2x/7)-(6/5)=(9/10)

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Solution for (2x/7)-(6/5)=(9/10) equation:



(2x/7)-(6/5)=(9/10)
We move all terms to the left:
(2x/7)-(6/5)-((9/10))=0
We add all the numbers together, and all the variables
(+2x/7)-(+6/5)-((+9/10))=0
We get rid of parentheses
2x/7-6/5-((+9/10))=0
We calculate fractions
100x^2/()+()/()+()/()=0
We add all the numbers together, and all the variables
100x^2/()+2=0
We multiply all the terms by the denominator
100x^2+2*()=0
We add all the numbers together, and all the variables
100x^2=0
a = 100; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·100·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{200}=0$

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