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(2x/7)-5=x
We move all terms to the left:
(2x/7)-5-(x)=0
We add all the numbers together, and all the variables
(+2x/7)-x-5=0
We add all the numbers together, and all the variables
-1x+(+2x/7)-5=0
We get rid of parentheses
-1x+2x/7-5=0
We multiply all the terms by the denominator
-1x*7+2x-5*7=0
We add all the numbers together, and all the variables
2x-1x*7-35=0
Wy multiply elements
2x-7x-35=0
We add all the numbers together, and all the variables
-5x-35=0
We move all terms containing x to the left, all other terms to the right
-5x=35
x=35/-5
x=-7
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