(2x/x+1)+(5/2x)=2

Solution for (2x/x+1)+(5/2x)=2 equation:

(2x/x+1)+(5/2x)=2

We move all terms to the left:

(2x/x+1)+(5/2x)-(2)=0


Domain of the equation: x+1)!=0

x∈R



Domain of the equation: 2x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(2x/x+1)+(+5/2x)-2=0

We get rid of parentheses

2x/x+5/2x+1-2=0

We calculate fractions


4x^2/2x^2+5x/2x^2+1-2=0

We add all the numbers together, and all the variables

4x^2/2x^2+5x/2x^2-1=0

We multiply all the terms by the denominator


4x^2+5x-1*2x^2=0

Wy multiply elements

4x^2-2x^2+5x=0

We add all the numbers together, and all the variables

2x^2+5x=0

a = 2; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·2·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*2}=\frac{-10}{4}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*2}=\frac{0}{4}
=0
$