(2x/x+3)=(-6/x+3)-2

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Solution for (2x/x+3)=(-6/x+3)-2 equation: 



(2x/x+3)=(-6/x+3)-2

We move all terms to the left:

(2x/x+3)-((-6/x+3)-2)=0



Domain of the equation: x+3)!=0

x∈R





Domain of the equation: x+3)-2)!=0

x∈R



We get rid of parentheses

2x/x-((-6/x+3)-2)+3=0

We calculate fractions


2x^2/x^2+(-((-6*x)/x^2+3=0

We add all the numbers together, and all the variables

2x^2/x^2+(-((-6x)/x^2+3=0

We calculate fractions

We do not support expression: x^4

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