(2x/x+3)=-6/x+3-2

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Solution for (2x/x+3)=-6/x+3-2 equation: 



(2x/x+3)=-6/x+3-2

We move all terms to the left:

(2x/x+3)-(-6/x+3-2)=0



Domain of the equation: x+3)!=0

x∈R





Domain of the equation: x+3-2)!=0

We move all terms containing x to the left, all other terms to the right

x-2)!=-3

x∈R



We add all the numbers together, and all the variables

(2x/x+3)-(-6/x+1)=0

We get rid of parentheses

2x/x+6/x+3-1=0

We multiply all the terms by the denominator


2x+3*x-1*x+6=0

We add all the numbers together, and all the variables

4x+6=0

We move all terms containing x to the left, all other terms to the right

4x=-6

x=-6/4

x=-1+1/2

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