(2x2+6)=(x2+31)

Solution for (2x2+6)=(x2+31) equation:

(2x^2+6)=(x2+31)

We move all terms to the left:

(2x^2+6)-((x2+31))=0

We add all the numbers together, and all the variables

-((+x^2+31))+(2x^2+6)=0

We get rid of parentheses

-((+x^2+31))+2x^2+6=0


We calculate terms in parentheses: -((+x^2+31)), so:

(+x^2+31)

We get rid of parentheses

x^2+31

Back to the equation:

-(x^2+31)


We get rid of parentheses

2x^2-x^2-31+6=0

We add all the numbers together, and all the variables

x^2-25=0

a = 1; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·1·(-25)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10}{2*1}=\frac{-10}{2}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10}{2*1}=\frac{10}{2}
=5
$