(2x2+7x+10)=(x2+2x-9)

Solution for (2x2+7x+10)=(x2+2x-9) equation:

(2x^2+7x+10)=(x2+2x-9)

We move all terms to the left:

(2x^2+7x+10)-((x2+2x-9))=0

We add all the numbers together, and all the variables

-((+x^2+2x-9))+(2x^2+7x+10)=0

We get rid of parentheses

-((+x^2+2x-9))+2x^2+7x+10=0


We calculate terms in parentheses: -((+x^2+2x-9)), so:

(+x^2+2x-9)

We get rid of parentheses

x^2+2x-9

Back to the equation:

-(x^2+2x-9)


We add all the numbers together, and all the variables

2x^2+7x-(x^2+2x-9)+10=0

We get rid of parentheses

2x^2-x^2+7x-2x+9+10=0

We add all the numbers together, and all the variables

x^2+5x+19=0

a = 1; b = 5; c = +19;
Δ = b2-4ac
Δ = 52-4·1·19
Δ = -51
Delta is less than zero, so there is no solution for the equation